Let f:[-3,1] \to R be given as f(x)=\\begin{array}{cc}\min \{(x+6) & x^{2\end{array}\}, , -3 \leq x \leq 0 ; \max \\sqrt{x}, x^{2}\}, , 0 \leq x \leq 1 \} If the area bounded by y=f(x) and x-axis is A, then the value of 6 A is equal to [17 Mar 2021 Shift 2]

Area Under The Curves Part 1

Section: Mathematics

Question : 49 of 100

Marks: +1, -0

Let f:[−3,1]→R be given as f(x)={

min{(x+6),x2}	‌	−3≤x≤0
max{√x,x2}	‌	0≤x≤1

}
If the area bounded by y=f(x) and x-axis is A, then the value of 6A is equal to

[17 Mar 2021 Shift 2]

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