Let the function f(x)=\frac{x}{3}+\frac{3}{x}+3, x \neq 0 be strictly increasing in (-\infty, \alpha_1) \cup (\alpha_2, \infty) and strictly decreasing in (\alpha_3, \alpha_4) \cup (\alpha_4, \alpha_5). Then \sum_{i=1}^{5} \alpha_i^2 is equal to [8 Apr 2025 Shift 2]

Application of Derivatives Part 3

Section: Mathematics

Question : 8 of 30

Marks: +1, -0

Let the function f(x)=‌

+‌

+3,x≠0 be strictly increasing in (−∞,α1)∪(α2,∞) and strictly decreasing in (α3,α4)∪(α4,α5). Then

∑

i=1

αi2 is equal to

[8 Apr 2025 Shift 2]

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