Let A=\{(\alpha, \beta) \in \mathbb{R} \times \mathbb{R}:|\alpha-1| \leq 4 and |\beta-5| \leq 6\} and B= \{(\alpha, \beta) \in \mathbb{R} \times \mathbb{R}: 16(\alpha-2)^2+9(\beta-6)^2 \leq 144\}. Then [7 Apr 2025 Shift 2]

A \cup B=\{(x, y):-4 \leq x \leq 4,-1 \leq y \leq 11\}

Neither A \subset B nor B \subset A

Sets and Relations Part 1

Section: Mathematics

Question : 12 of 112

Marks: +1, -0

Let A={(α,β)∈ℝ×ℝ:|α−1|≤4 and |β−5|≤6} and B={(α,β)∈ℝ×ℝ:16(α−2)2+9(β−6)2≤144}.
Then

[7 Apr 2025 Shift 2]

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