Sequences and Series Part 2

Section: Mathematics
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Question : 5 of 100
 
Marks: +1, -0
If gcd(m,n)=1 and
12−22+32−42+......+(2021)2−(2022)2+(2023)2=1012m2n
then m2−n2 is equal to :
[6-Apr-2023 shift 2]
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