Quadratic Equation and Inequalities Part 2

Section: Mathematics

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Question : 68 of 93

Marks: +1, -0

If ‌

1

(20−a)(40−a)

+‌

1

(40−a)(60−a)

+...+‌

1

(180−a)(200−a)

=‌

1

256

, then the maximum value of a is :

[29-Jul-2022-Shift-1]

198
202
212
218

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