Let \alpha and \beta be the roots of the equation x^2+2 a x+(3 a+10)=0 such that \alpha< 1< \beta. Then the set of all possible values of a is : [21 Jan 2026 Shift 2]

Correct Answer is : (−∞,−115)

(-\infty, \frac{-11}{5}) \cup(5, \infty)

Quadratic Equation and Inequalities Part 2

Section: Mathematics

Question : 10 of 93

Marks: +1, -0

Let α and β be the roots of the equation x2+2ax+(3a+10)=0 such that α<1<β. Then the set of all possible values of a is :

[21 Jan 2026 Shift 2]

Go to Question:

Prev Question

Next Question