Let \\alpha, \\beta be two roots of the equation {x}^{2}+(20)^{1 \/ 4} {x}+(5)^{1 \/ 2}=0. Then \\alpha^{8}+\\beta^{8} is equal to [27 Jul 2021 Shift 1]

Quadratic Equation and Inequalities Part 1

Section: Mathematics

Question : 9 of 100

Marks: +1, -0

Let α,β be two roots of the equation x2+(20)1∕4x+(5)1∕2=0. Then α8+β8 is equal to

[27 Jul 2021 Shift 1]

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