Let \alpha=\frac{(4 !) !}{(4 !)^{3 !}} and \beta=\frac{(5 !) !}{(5 !)^{4 !}}. Then : [27-Jan-2024 Shift 2]

Correct Answer is : α∈N and β∈N

\alpha \in {\N} and \beta \notin {\N}

\alpha \notin {\N} and \beta \in {\N}

\alpha \in {\N} and \beta \in {\N}

\alpha \notin {\N} and \beta \notin {\N}

Permutations and Combinations Part 2

Section: Mathematics

Question : 54 of 110

Marks: +1, -0

Let α=‌

(4!)!

(4!)3!

and β=‌

(5!)!

(5!)4!

. Then :

[27-Jan-2024 Shift 2]

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