Permutations and Combinations Part 1

Section: Mathematics

Question : 1 of 100

Marks: +1, -0

Let b1b2b3b4 be a 4-element permutation with bi∈{1,2,3,.......,100} for 1≤i≤4 and bi≠bj for i≠j, such that either b1,b2, b3 are consecutive integers or b2,b3,b4 are consecutive integers. Then the number of such permutations b1b2b3b4 is equal to___

[29-Jun-2022-Shift-1]

Your Answer:

Validate

Go to Question:

Next Question