A circle of radius 2 unit passes through the vertex and the focus of the parabola y^2=2 x and touches the parabola y=(x-\frac{1}{4})^2+\alpha, where \alpha>0 . Then (4 \alpha-8)^2 is equal to___ [27-Jun-2022-Shift-1]

Parabola Part 1

Section: Mathematics

Question : 26 of 100

Marks: +1, -0

A circle of radius 2 unit passes through the vertex and the focus of the parabola y2=2x and touches the parabola y=(x−‌

)2+α, where α>0. Then (4α−8)2 is equal to___

[27-Jun-2022-Shift-1]

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