Let S be the focus of the hyperbola \frac{x^2}{3}-\frac{y^2}{5}=1, on the positive {\x}-axis. Let {\C} be the circle with its centre at {\A}(\sqrt{6}, \sqrt{5}) and passing through the point {\S}. if {\O} is the origin and {\SAB} is a diameter of {\C} then the square of the area of the triangle OSB is equal to - [8 Apr 2024 Shift 2]

Hyperbola

Section: Mathematics

Question : 18 of 92

Marks: +1, -0

Let S be the focus of the hyperbola ‌

−‌

=1, on the positive x-axis. Let C be the circle with its centre at A(√6,√5) and passing through the point S. if O is the origin and SAB is a diameter of C then the square of the area of the triangle OSB is equal to -

[8 Apr 2024 Shift 2]

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