Let {\p}, {\q} \in \mathbb{R} and (1-\sqrt{3} {\i})^{200}=2^{199}( {\p}+ {\iq}), {\i}=\sqrt{-1} Then {\p}+ {\q}+ {\q}^2 and {\p}- {\q}+ {\q}^2 are roots of the equation. [24-Jan-2023 Shift 1]

Correct Answer is : x2−4x+1=0

Complex Numbers Part 2

Section: Mathematics

Question : 77 of 97

Marks: +1, -0

Let p,q∈ℝ and (1−√3i)200=2199(p+iq), i=√−1 Then p+q+q2 and p−q+q2 are roots of the equation.

[24-Jan-2023 Shift 1]

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