Let A=\{z \in C:|\frac{z+1}{z-1}|< 1\} and B=\{z \in C: \arg (\frac{z-1}{z+1})=\frac{2 \pi}{3}\}. Then {\A} \cap {\B} is : [26-Jun-2022-Shift-1]

Correct Answer is : a portion of a circle centred at (0,−1√3) that lies in the second quadrant only

a portion of a circle centred at (0,-\frac{1}\sqrt{3}) that lies in the second and third quadrants only

a portion of a circle centred at (0,-\frac{1}\sqrt{3}) that lies in the second quadrant only

a portion of a circle of radius \frac{2}\sqrt{3} that lies in the third quadrant only

Complex Numbers Part 1

Section: Mathematics

Question : 2 of 100

Marks: +1, -0

Let A={z∈C:|‌

z+1

z−1

|<1} and B={z∈C:arg(‌

z−1

z+1

)=‌

2π

}. Then A∩B is :

[26-Jun-2022-Shift-1]

a portion of a circle centred at (0,−‌
1
√3
) that lies in the second and third quadrants only
a portion of a circle centred at (0,−‌
1
√3
) that lies in the second quadrant only
an empty
a portion of a circle of radius ‌
2
√3
that lies in the third quadrant only

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