Binomial Theorem Part 2

Section: Mathematics

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Question : 90 of 100

Marks: +1, -0

n

∑

i,j=0

i≠j

‌nCi‌nCj is equal to

[26-Jul-2022-Shift-2]

22n−‌2nCn
22n−1−‌2n−1Cn−1
22n−‌
1
2
‌2nCn
22n−1+2n−1Cn

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