Binomial Theorem Part 1

Section: Mathematics
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Question : 56 of 100
 
Marks: +1, -0
Let Sn = 1 + q + q2 + ... + qn and tn = 1 + (
q+1
2
)
+ (
q+1
2
)
2
+ ... + (
q+1
2
)
n

where q is a real number and q ≠ 1. If
101
‌
C1
+
101
‌
C2
.S1
+ ... +
101
‌
C101
.S100
= αT100 , then α is equal to :
[11 Jan 2019 Shift 2]
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