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Question : 16 of 100
Marks:
+1,
-0
Solution:
Given,
⇒(1−x)n=(−1)t⋅Ctxt x=‌ ⇒(1−‌)n=C0−C1(‌)+C2(‌)2... ⇒‌‌x=‌⇒‌‌x=‌ (1−‌)n=C0−C1(‌)+C2(‌)2⋯ Similarly, we will get
⇒A=‌+‌+‌+‌+‌ ⇒A=‌⋅[‌] ⇒A=(‌)(‌)(‌) ⇒A=(‌)(‌) ∵‌‌63A=1−‌ ⇒‌‌63‌=‌ ⇒(‌)(1−‌)=(1−‌) n=6, satisfies the equation.
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