Haloalkanes and Haloarenes Part 1

On reaction of haloalkane with methoxide ion, alkene is formed. Mechanism ●

⊖

O

CH3 will act as a base due to its small size and high electron density and therefore, abstracts proton to form double bond which is in conjugation with aromatic ring.
● The

⊖

O

CH3 when acts as nucleophile undergoes nucleophilic substitution and replaces Br⊖ to form ether, which is a minor product. So, option (b) is correct.