Electrochemistry Part 2

Section: Chemistry
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Question : 85 of 117
 
Marks: +1, -0
The electrode potential of the following half cell at
‌298K‌. ‌
‌X|X2+(0.001M)|Y2+(0.01M)|Y
is _______ ×10−2V (Nearest integer).
Given: Ex2+∣x0=−2.36V
EY2+‌Y0=+0.36V
‌
2.303‌RT
F
=0.06V
[30-Jan-2023 Shift 2]
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