Electrochemistry Part 2

Section: Chemistry

© examsiri.com

Question : 74 of 117

Marks: +1, -0

FeO42−

+2.2V

─────▶

Fe3+

+0.70V

─────▶

Fe2+

−0.45V

─────▶

Fe0
EFeO42−∕Fe2+∘ is x×10−3V.
The value of x is _______

[10-Apr-2023 shift 1]

Your Answer:

Go to Question:

Prev Question

Next Question