Reduction potential of ions are given below: \table {\ClO}_4^{-}, {\IO}_4^{-}, {\BrO}_4^{-} ; {\E}^{\circ}=1.19 {\V}, {\E}^{\circ}=1.65 {\V}, {\E}^{\circ}=1.74 {\V} The correct order of their oxidising power is: [30-Jan-2024 Shift 2]

Correct Answer is : BrO4−>IO4−>ClO4−

{\ClO}_4^{-}> {\IO}_4^{-}> {\BrO}_4^{-}

{\BrO}_4^{-}> {\IO}_4^{-}> {\ClO}_4^{-}

{\BrO}_4^{-}> {\ClO}_4^{-}> {\IO}_4^{-}

{\IO}_4^{-}> {\BrO}_4^{-}> {\ClO}_4^{-}

Electrochemistry Part 2

Section: Chemistry

Question : 61 of 117

Marks: +1, -0

Reduction potential of ions are given below:

ClO4−	IO4−	BrO4−
E∘=1.19V	E∘=1.65V	E∘=1.74V

The correct order of their oxidising power is:

[30-Jan-2024 Shift 2]

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