The potential for the given half cell at 298 {\K} is \times 10^{-2} {\V}. 2 {\H}^{+}{ }_{( {\aq})}+2 {\e}^{-} \rightarrow {\H}_2( {\g}) [ {\H}^{+}] =1 {\M}, {\P}_{ {\H}_2}=2 {\atm} (Given: 2.303 {\RT} \/ {\F}=0.06 {\V}, \log 2=0.3 ) [1-Feb-2024 Shift 1]

Electrochemistry Part 2

Section: Chemistry

Question : 55 of 117

Marks: +1, -0

The potential for the given half cell at 298K is ×10−2V.
2H+‌(aq)+2e−⟶H2(g)
[H+]=1M,PH2=2‌atm
(Given: 2.303‌RT∕F=0.06V,log‌2=0.3 )

[1-Feb-2024 Shift 1]

Go to Question:

Prev Question

Next Question