Electrochemistry Part 2

Section: Chemistry
© examsiri.com
Question : 16 of 117
 
Marks: +1, -0
1 Faraday electricity was passed through Cu2+(1.5M,1L)∕Cu and 0.1 Faraday was passed through Ag+(0.2M,1L)∕Ag electrolytic cells. After this the two cells were connected as shown below to make an electrochemical cell. The emf of the cell thus formed at 298 K is ____ mV (nearest integer)
‌ Given : ‌ECu2+∕Cu∘=0.34V
EAg+∕Ag∘=0.8V
‌
2.303‌RT
F
=0.06V
[7 Apr 2025 Shift 1]
  • Your Answer:
Go to Question: