For the cell {Cu}({s})|{Cu}^{2+}({aq})(0.1 {M}) \parallel{Ag}^{+}({aq})(0.01 {M}) | {Ag}({s}) the cell potential {E}_{1}=0.3095 {V}For the cell {Cu}({s})|{Cu}^{2+}({aq})(0.01 {M})\parallel{Ag}^{+}({aq})(0.001 {M}) | {Ag}({s}) the cell potential =───10^{-2} {V}. (Round off the Nearest Integer). [ \Use: {2.303 {RT}}/{{F}}=0.059] [27 Jul 2021 Shift 2]

Electrochemistry Part 1

Section: Chemistry

Question : 7 of 100

Marks: +1, -0

For the cell
Cu(s)|Cu2+(aq)(0.1M)∥Ag+(aq)(0.01M) |Ag(s)
the cell potential E1=0.3095VFor the cell
Cu(s)|Cu2+(aq)(0.01M)∥Ag+(aq)(0.001M) |Ag(s)
the cell potential =───10−2V. (Round off the Nearest Integer).
[Use:

2.303RT

=0.059]

[27 Jul 2021 Shift 2]

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