Electrochemistry Part 1

Section: Chemistry
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Question : 43 of 100
 
Marks: +1, -0
Given that
EΘO2∕H2O=+1.23V
EΘS2O82−∕SO42−=2.05V
EΘBr2∕Br=+1.09V
EΘAu3+∕Au=+1.4V
The strongest oxidizing agent is:
[8 Apr 2019 Shift 1]
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