For the galvanic cell, {\Zn}({\s})+{\Cu}^{2+}(0.02 {\M}) \to {\Zn}^{2+}(0.04 {\M})+{\Cu}({\s}), \E_{{\cell }}=..........\times10^{-2} {\V}.( Nearest integer ) [ Use \E^\circ_{{\Cu} \/ {\cu}^{2+}}=-0.34 {\V}, \E^\circ_{{\Zn} \/ {\Zn}^{2+}}=+0.76 {\V}, \frac{2.303 \R \T}{\F}=0.059 {\V}] [26 Aug 2021 Shift 2]

Electrochemistry Part 1

Section: Chemistry

Question : 4 of 100

Marks: +1, -0

For the galvanic cell,
Zn(s)+Cu2+(0.02M)→Zn2+(0.04M)+Cu(s),
Ecell=..........×10−2V.( Nearest integer )
[ Use E°Cu∕cu2+=−0.34V,E°Zn∕Zn2+=+0.76V,

2.303RT

=0.059V]

[26 Aug 2021 Shift 2]

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