For the disproportionation reaction 2 {Cu}^{+}( {aq})⇌{Cu}( {s})+ {Cu}^{2+}( {aq}) at 298 {K}ln {K} (where {K} is the equilibrium constant) is _____\times 10^{-1} Given ({E}^\circ_{ {Cu}^{2+} \/ {Cu}^{+}} =0.16 {V}, {E}^\circ_{ {Cu}^{+} \/ {Cu}} =0.52 {V}, {{RT}}/{ {F}}=0.025 ) [2 Sep 2020 Shift 2]

Electrochemistry Part 1

Section: Chemistry

Question : 31 of 100

Marks: +1, -0

For the disproportionation reaction
2Cu+(aq)⇌Cu(s)+Cu2+( aq)
at 298 Kln K (where K is the equilibrium constant) is _____×10−1
Given
(E°Cu2+∕Cu+=0.16V, E°Cu+∕Cu=0.52V,

=0.025)

[2 Sep 2020 Shift 2]

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