For the reaction, 2 {Fe}^{3+}(a q)+2 {l}^{-}(a q) \rightarrow 2 {Fe}^{2+}(a q)+ {I}_{2}(s) The magnitude of the standard molar Gibbs free energy change, ∆, G_{m}^{\circ}=-. . . . . . . . . . kJ (Round off to the nearest integer). [\table E_{ {Fe}^{2+} \/ {Fe}( {s})}^{\circ}=-0.440 {V}\text{;} , E_{ {Fe}^{3+} {/} {Fe}( {s})}^{\circ}=-0.036 {V} ; E_{ {I}_{2} {/} 2 {I}^{-}}=0.539 {V} \text{;} , F=96500 {C}] [18 Mar 2021 Shift 1]

Electrochemistry Part 1

Section: Chemistry

Question : 13 of 100

Marks: +1, -0

For the reaction,
2Fe3+(aq)+2l−(aq)⟶2Fe2+(aq)+I2(s)
The magnitude of the standard molar Gibbs free energy change,
∆,Gm∘=−. . . . . . . . . . kJ
(Round off to the nearest integer).

[

EFe2+∕Fe(s)∘=−0.440V;	EFe3+/Fe(s)∘=−0.036V
EI2/2I−=0.539V;	F=96500C

]

[18 Mar 2021 Shift 1]

Your Answer:

Validate

Go to Question:

Prev Question

Next Question