Chemical Kinetics Part 2

Section: Chemistry
© examsiri.com
Question : 97 of 111
 
Marks: +1, -0
The activation energy of one of the reactions in a biochemical process is 532611Jmol−1. When the temperature falls from 310 K to 300K, the change in rate constant observed is k300=x×10−3k310. The value of x is______
[Given .:ln‌10=2.3,R=8.3JK−1mol−1]
[29-Jun-2022-Shift-1]
  • Your Answer:
Go to Question: