An organic compound undergoes first order decomposition. The time taken for decomposition to (\frac{1}{8}) ^{\text{th }} and (\frac{1}{10}) ^{\text{th }} of its initial concentration are t_{1 \/ 8} and t _{1 \/ 10} respectively. What is the value of {t_{1 \/ 8}}/{t_{1 \/ 10}} \times 10 ? (\log 2=0.3) [28 Jan 2026 Shift 1]

Chemical Kinetics Part 2

Section: Chemistry

Question : 2 of 111

Marks: +1, -0

An organic compound undergoes first order decomposition. The time taken for decomposition to (‌

)‌th ‌ and (‌

)‌th ‌ of its initial concentration are t1∕8 and t1∕10 respectively.
What is the value of ‌

t1∕8

t1∕10

×10 ?
(log‌2=0.3)

[28 Jan 2026 Shift 1]

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