Chemical Kinetics Part 1

Given, the reaction 2A+B2⟶2AB is an elementary reaction.

So, rate of reaction
=k[A]2[B2]
Initial rate =k(a∕V)2(b/V)1
where, a and b are the number of moles of A and B and V is the volume.
On reducing the volume by a factor of 3 , the concentrations of A and B2 will become 3 times
Final rate =k(3a∕V)2(3b/V)1 32×3k(‌

a

V

)2(‌

b

V

)1=27× initial rate
Hence, the rate becomes 32×3=27 times of initial rate.