The first order rate constant for the decomposition of {\CaCO}_{3} at 700 {\K} is 6.36 \times10^{-3} {\s}^{-1} and activation energy is 209 {\kJ} {\mol}^{-1}. Its rate constant (in {\s}^{-1}) at 600 {\K} is x \times10^{-6}. The value of x is ......... (Nearest integer) [Given, \R=8.31 \JK^{-1}\mol^{-1},\log6.36\times10^{-3} =-2.19,10^{-4.79}=1.62\times10^{-5}] [27 Aug 2021 Shift 2]

Chemical Kinetics Part 1

Section: Chemistry

Question : 1 of 100

Marks: +1, -0

The first order rate constant for the decomposition of CaCO3 at 700K is 6.36×10−3s−1 and activation energy is 209‌kJ‌mol−1. Its rate constant (in s−1) at 600K is x×10−6. The value of x is ......... (Nearest integer)
[Given, R=8.31JK−1mol−1,log‌6.36×10−3 =−2.19,10−4.79=1.62×10−5]

[27 Aug 2021 Shift 2]

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