Consider the following pairs of electrons (A) ( {a}) {n}=3, l=1, {m}_{1}=1, {m}_{ {s}}=+\frac{1}{2} (b) n=3, l=2, m_{1}=1, m_{s}=+\frac{1}{2} (B) (a) {n}=3, l=2, {m}_{1}=-2, {m}_{ {s}}=-\frac{1}{2} (b) {n}=3, l=2, {m}_{1}=-1, {m}_{ {s}}=-\frac{1}{2} (C) ( {a}) {n}=4, l=2, {m}_{1}=2, {m}_{ {s}}=+\frac{1}{2} (b) {n}=3, l=2, {m}_{1}=2, {m}_{ {s}}=+\frac{1}{2} The pairs of electrons present in degenerate orbitals is/are : [24-Jun-2022-Shift-1]

Structure of Atom Part 1

Section: Chemistry

Question : 5 of 100

Marks: +1, -0

Consider the following pairs of electrons
(A)
(a)n=3,l=1,m1=1,ms=+‌

(b) n=3,l=2,m1=1,ms=+‌

(B)
(a) n=3,l=2,m1=−2,ms=−‌

(b) n=3,l=2,m1=−1,ms=−‌

(b) n=3,l=2,m1=2,ms=+‌

The pairs of electrons present in degenerate orbitals is/are :

[24-Jun-2022-Shift-1]

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