Structure of Atom Part 1

According to Hysenberg's Uncertainty Principal
∆x.∆p≥‌

h

4π

Where ∆x is uncertainty in position and ∆p is uncertainty in momentum and as in momentum m (mass of object) is always same so we can say
∆x⋅m⋅∆v≥‌

h

4π

Mass of the particle (m)=25g=0.025‌kg
Position of the particle (∆x)=10−5m
∆x⋅∆p=‌

h

4π

∆x⋅m⋅∆v=‌

h

4π

∆v=‌

h

4×∆x×m×π

∆v=‌

6.6×10−34

4×10−5×0.025×3.14

∆v=2.1×10−28