The molarity of the solution prepared by dissolving 6.3 {\g} of oxalic acid ({\H}_{2} {\C}_{2} {\O}_{4} .2 {\H}_{2} {\O}) in 250 {\mL} of water in {\mol} {\L}^{-1} is x \times10^{-2}. The value of x is ......... (Nearest integer) [Atomic mass{\H}=1.0, {\C}=12.0, {\O}=16.0] [31 Aug 2021 Shift 1]

Some Basic Concepts of Chemistry Part 1

Section: Chemistry

Question : 2 of 100

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The molarity of the solution prepared by dissolving 6.3g of oxalic acid (H2C2O4.2H2O) in 250‌mL of water in mol‌L−1 is x×10−2. The value of x is ......... (Nearest integer)
[Atomic massH=1.0,C=12.0,O=16.0]

[31 Aug 2021 Shift 1]

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