{\K}_{\text{sp }} for {\Cr}( {\OH})_3 is 1.6 \times 10^{-30}. What is the molar solubility of this salt in water? [24 Jan 2025 Shift 1]

Correct Answer is : 4√1.6×10−3027

\sqrt[4]{\frac{1.6 \times 10^{-30}}{27}}

Ionic Equilibrium Part 2

Section: Chemistry

Question : 16 of 34

Marks: +1, -0

K‌sp ‌ for Cr(OH)3 is 1.6×10−30. What is the molar solubility of this salt in water?

[24 Jan 2025 Shift 1]

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