The {\K}_{\text{sp}} for bismuth sulphide (\Bi_2 {\S}_3) is 1.08 \times 10^{-73}. The solubility of {\Bi}_2 {\S}_3 in {\mol} {\L}^{-1} at 298 {\K} is [25-Jun-2022-Shift-2]

Correct Answer is : 1.0×10−15

Ionic Equilibrium Part 1

Section: Chemistry

Question : 27 of 100

Marks: +1, -0

The Ksp for bismuth sulphide (Bi2S3) is 1.08×10−73. The solubility of Bi2S3 in mol‌L−1 at 298K is

[25-Jun-2022-Shift-2]

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