Given : ∆ {\H}_{ { sub}}^{\Theta}[ {\C}(\text{ graphite })]=710 {\kJ} {\mol}^{-1} ∆_{ {\C}- {\H}} {\H}^{\Theta}=414 {\kJ} {\mol}^{-1} ∆_{ {\H}- {\H}} {\H}^{\Theta}=436 {\kJ} {\mol}^{-1} ∆_{ {\C}= {\C}} {\H}^{\Theta}=611 {\kJ} {\mol}^{-1} The ∆ {\H}_{ {\f}}^{\Theta} for {\CH}_2= {\CH}_2 is \_\_\_\_ {\kJ} {\mol}^{-1} (nearest integer value) [3 Apr 2025 Shift 1]

Chemical Thermodynamics Part 3

Section: Chemistry

Question : 22 of 22

Marks: +1, -0

Given :
‌∆H subΘ[C(‌ graphite ‌)]=710‌kJ‌mol−1
‌∆C−HHΘ=414‌kJ‌mol−1
‌∆H−HHΘ=436‌kJ‌mol−1
‌∆C=CHΘ=611‌kJ‌mol−1 The ∆HfΘ for CH2=CH2 is ____ kJ‌mol−1 (nearest integer value)

[3 Apr 2025 Shift 1]

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