An ideal gas undergoes a cyclic transformation starting from the point A and coming back to the same point by tracing the path A \rightarrow B \rightarrow C \rightarrow D \rightarrow A as shown in the three cases above. Choose the correct option regarding ∆ {\U} : [28 Jan 2025 Shift 2]

Correct Answer is : ∆U( Case-I )=∆U( Case-II )=∆U( Case-III )

∆ U( Case-I )=∆ U( Case-II )=∆ U( Case-III )

∆ {\U}( Case-III )>∆ {\U}( Case-II )>∆ {\U}( Case-I )

∆ {\U}( Case-I) >∆ {\U}(gt;∆ {\U}( Case-III )>∆ {\U}( Case-II )

∆ {\U}( Case-I )>∆ {\U}( Case-II )>∆ {\U}( Case-III )

Chemical Thermodynamics Part 2

Section: Chemistry

Question : 8 of 100

Marks: +1, -0

An ideal gas undergoes a cyclic transformation starting from the point A and coming back to the same point by tracing the path A⟶B⟶C⟶D⟶A as shown in the three cases above.

Choose the correct option regarding ∆U :

[28 Jan 2025 Shift 2]

∆U( Case-I )=∆U( Case-II )=∆U( Case-III )
∆U( Case-III )>∆U( Case-II )>∆U( Case-I )
∆U( Case-I) >∆U( Case-III )>∆U( Case-II )
∆U( Case-I )>∆U( Case-II )>∆U( Case-III )

Validate

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