Chemical Thermodynamics Part 2
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Question : 41 of 100
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For a certain thermochemical reaction M → N T = 400 K , ∆ H ⊖ = 77.2 kJ mol − 1 , ∆ S = 122 JK − 1 log ( log K ) × 10 − 1
[27-Jan-2024 Shift 2]
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