Chemical Bonding and Molecular Structure Part 1

(A) Ne2(20e−)
⇒σ1s2σ*1s2σ2s2σ*2s2σ2pz2π2px2π2py2π*2px2π*2py2σ*2pz2
Bond order =‌

10−10

2

=0⇒ (iii) of List-II.
(B) N2(14e−)
⇒σ1s2σ*1s2σ2s2σ*2s2π2px2,π2py2σ2p
Bond order =‌

10−4

2

=3⇒ (iv) of List-II.
(c) F2(18e−)
⇒σ1s2σ*1s2σ2s2σ*2s2σ2pz2π2px2π2py2π*2py2π*2
Bond order =‌

10−8

2

=1⇒ (i) of List-II.
(d) O2(16e−)
⇒σ1s2σ*1s2σ2s2σ*2s2σ2pz‌2π2px‌2π2py‌2π*2px‌1π*2py‌1
Bond order =‌

10−6

2

=2⇒ (ii) of List-II.
The correct matching is option (a).
No. of electrons in antibonding
MO (Molecular Orbital)
Note : Bond order =‌

−‌ No. of electrons in bonding MO ‌

2