If \frac{dy}{dx}=\frac{xy}{x^2+y^2};y(1)=1 ; then a value of x satisfying y(x) = e is : [9 Jan 2020 Shift 2]

JEE Main 9 Jan 2020 Shift 2 Solved Paper

Section: Mathematics

Question : 63 of 75

Marks: +1, -0

x2+y2

;y(1)=1 ; then a value of x satisfying y(x) = e is :

[9 Jan 2020 Shift 2]

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