JEE Main 9 Jan 2020 Shift 1 Solved Paper

Section: Mathematics

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Question : 70 of 75

Marks: +1, -0

If for all real triplets (a, b, c), f(x)=a+bx+cx2; the

1

∫

0

f(x)dx is equal to :

[9 Jan 2020 Shift 1]

1
2
{f(1)+3f(
1
2
)}
2{3f(1)+2f(
1
2
)}
1
6
{f(0)+f(1)+4f(
1
2
)}
1
3
{f(0)+f(
1
2
)}

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