The electric fields of two plane electromagnetic plane waves in vacuum are given by E_1^{\to}=E_0j^{\^}\cos(\omegat-kx) and E_2^{\to}=E_0k^{\^}\cos(\omegat-ky) At t = 0, a particle of charge q is at origin with a velocity v^{\to} = 0.8cj^{\^} (c is the speed of light in vacuum). The instantaneous force experienced by the particle is : [9 Jan 2020 Shift 1]

Correct Answer is : E0q(0.8^i+^j+0.2^k)

E_0q(-0.8i^{\^} + j^{\^} + k^{\^} )

E_0q( 0.8i^{\^} - j^{\^} + 0.4k^{\^} )

E_0q( 0.8i^{\^} + j^{\^} + 0.2k^{\^} )

E_0q(0.4i^{\^} -3 j^{\^} +0.8 k^{\^} )

JEE Main 9 Jan 2020 Shift 1 Solved Paper

Section: Physics

Question : 4 of 75

Marks: +1, -0

The electric fields of two plane electromagnetic plane waves in vacuum are given by

→

=E0

‌cos(ωt−kx) and

→

=E0

‌cos(ωt−ky)
At t = 0, a particle of charge q is at origin with a velocity

→

=0.8c

(c is the speed of light in vacuum). The instantaneous force experienced by the particle is :

[9 Jan 2020 Shift 1]

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