JEE Main 9 Jan 2020 Shift 1 Solved Paper
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Question : 18 of 75
Marks:
+1,
-0
An electric dipole of moment
= ( −
− 3
+ 2
) × 10 − 29 C .m is at the origin (0, 0, 0). The electric field due to this dipole at
= +
+ 3
+ 5
(note that
.
= 0 ) is parallel to:
[9 Jan 2020 Shift 1]
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