JEE Main 9 Jan 2020 Shift 1 Solved Paper

Section: Physics
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Question : 16 of 75
 
Marks: +1, -0
A charged particle of mass 'm' and charge 'q' moving under the influence of uniform electric field E
→
i
and a uniform magnetic field B
→
k
follows a trajectory from point P to Q as shown in figure. The velocities at P and Q are respectively, v
→
i
and −2v
→
j
. Then which of the following statements (A, B, C, D) are the correct ? (Trajectory shown is schematic and not to scale) :
(A) E=
3
4
(
mv2
qa
)

(B) Rate of work done by the electric field at P is
3
4
(
mv2
a
)

(C) Rate of work done by both the fields at Q is zero
(D) The difference between the magnitude of angular momentum of the particle at P and Q is 2 mav.
[9 Jan 2020 Shift 1]
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