JEE Main 9 Jan 2019 Shift 2 Solved Paper

Section: Mathematics

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Question : 52 of 90

Marks: +1, -0

If f (x) = ∫

5x8+7x6

(x2+1+2x7)2

dx , (x ≥ 0) and f (0) = 0 , then the value of f (1) is :

[9 Jan 2019 Shift 2]

-
1
2
1
2
-
1
4
1
4

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