JEE Main 9 Jan 2019 Shift 2 Solved Paper

Section: Mathematics

Question : 45 of 90

Marks: +1, -0

Let the equations of two sides of a triangle be 3x – 2y + 6 = 0 and 4x + 5y – 20 = 0. If the orthocentre of this triangle is at (1,1), then the equation of its third side is :

[9 Jan 2019 Shift 2]

122y – 26x – 1675 = 0
26x + 61y + 1675 = 0
122y + 26x + 1675 = 0
26x – 122y – 1675 = 0

Validate

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