JEE Main 9 Jan 2019 Shift 2 Solved Paper

Section: Mathematics
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Question : 32 of 90
 
Marks: +1, -0
If
Ï€
3
∫
0
atnθ
√2ksecθ
= 1 -
1
√2
, (k > 0) , then the value of k is :
[9 Jan 2019 Shift 2]
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