JEE Main 9 Jan 2019 Shift 1 Solved Paper

This is based upon Faraday's first law which states that "Mass of any substances deposited or liberated at any electrode is directly proportional to the quantity of electricity passed". The Faraday's laws of electrolysis are quantitative relationship based on the electrochemical research published by Micheal Faraday. They relate the amount of material produced at an electrode during an electrochemical reaction to the charge passed or equivalent, the average current and total time.
During charging,
Calculation:
Pb+so42−→PbSO4+2e
1F≡1g equivalent of PbSO4
=‌

1

2

mol of PbSO4⇒‌

303

2

gPbSO4
Therefore
0.05F=‌

303

2

‌‌0.05g of PbSO4
The amount of PbSO ‌4 electrolyzed by 0.05 Faraday of electricity will be 7.57 grams.