JEE Main 9 Jan 2019 Shift 1 Solved Paper
© examsiri.com
Question : 35 of 90
Marks:
+1,
-0
If y = y(x) is the solution of the differentialequation,
x
+ 2y = x 2 satisfying
y (1) = 1 , then y(
) is equal to :
x
y (1) = 1 , then y
[9-Jan-2019 Shift 1]
Go to Question: